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PV = nRT; units

  1. Feb 3, 2009 #1
    When using the ideal gas law equation and solving for V, with constant R = 8.314 J·mol−1·K−1, what are the resultant units? L or m3?

    I always remember it being in L, but wouldn't it be m3 based purely on the units being put into the equation?

    Other units I'm using:

    P: Pa (not kPa)
    T: K
     
    Last edited: Feb 4, 2009
  2. jcsd
  3. Feb 4, 2009 #2

    Borek

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    m3

    Trust your units :smile:

    For L one uses 8.314x103
     
  4. Feb 4, 2009 #3

    Gokul43201

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    Alternatively, there's also the other commonly used unit system, seen in R=0.0821 L-atm/(K-mol)
     
  5. Feb 4, 2009 #4

    nrqed

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    what you need to know to answer the question is that [itex] 1 Pa = 1 N/m^2 [/itex] (Newton per meter squared) and that [itex] 1 N = 1 J/m [/itex] so that [itex] 1 Pa = 1 J/m^3 [/itex] which shows that V comes out in [itex] m^3 [/itex]
     
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