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Pyramid of Egypt

  1. Jan 10, 2007 #1
    My Dad has a miniature Pyramid of Egypt. It is 3 inches in height. Dad was invited to display it at an exhibition. Dad felt it was too small and decided to build a scaled-up model of the Pyramid out of material whose density is (1/ 9) times the density of the material used for the miniature. He did a "back-of-the-envelope" calculation to check whether the model would be big enough.

    If the mass (or weight) of the miniature and the scaled-up model are to be the same, how many inches in height will be the scaled-up Pyramid? Give your answer to two places of decimal.
     
  2. jcsd
  3. Jan 10, 2007 #2
    9 inches!

    needed more text
     
  4. Jan 10, 2007 #3
    NO...Not right
     
  5. Jan 10, 2007 #4

    Hootenanny

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    81"

    (Again text limit)
     
  6. Jan 10, 2007 #5

    dextercioby

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    27 inches ?

    Daniel.
     
  7. Jan 10, 2007 #6
    How did you guys solve this? This one confused me for some reason. I know that all the dimensions between the two are proportional but I couldn't immediately see how to put that into the equations. A ratio would have worked but I didn't see one that helped solve the problem. I would sit down and think harder about it but I gotta go.
     
  8. Jan 10, 2007 #7
    Yea, it's 27", I have no idea what the heck I was thinking. Was just about to fall asleep and then I realized.
     
  9. Jan 10, 2007 #8
    No one gave me the right ans:
     
  10. Jan 10, 2007 #9
    what the hell, this question is making me mad. lol
     
  11. Jan 10, 2007 #10
    try it..................
     
  12. Jan 10, 2007 #11

    Hootenanny

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    6.24" text limit again

    [tex]3\cdot\left(\frac{1}{9}\right)^{-1/3}[/tex]
     
    Last edited: Jan 10, 2007
  13. Jan 10, 2007 #12
    6.24 it is.
     
  14. Jan 10, 2007 #13
    yes 6.24 is correct
    soln is as:
    Mass = Density x Volume; and
    Volume of model / Volume of miniature = (H of model / H of miniature)3.


    In the above equation, H is the characteristic dimension (say, height).

    If the mass is to be the same, then density is inversely proportional to volume. Also, the volumes are directly proportional to the cubes of the heights for objects that are geometrically similar. Therefore, the heights are seen to be inversely proportional to the cube roots of the densities. Thus,

    Height of model = Height of miniature x (Density of miniature / Density of model)1/3 or

    Height of model = 3 x [ 91/3 ] = 6.24 inches.
     
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