to work out a traingle side e.g. 5^{2} is it we first times the 3 by its self to get 9 and then we times the 4 x 4 to get 16. then we take away the difference to get 5^{2}? 9 + 16 = 25 Formula 3^{2} + 4^{2} = 5^{2} is this correct?
What you said was a little confusing, but here is a link to a simple statement of pythogrean's thereom: http://scidiv.bcc.ctc.edu/Math/Pythagoras.html
To work out the hypoteneuse's (the side which does not end in a 90 degree angle) length, you square the first side and add it to the square of the second side. Then take the square root of the third side. a^{2} + b^{2} = c^{2} 3^{2} + 4^{2} = c^{2} 9 + 16 = c^{2} c^{2}= 25 c = [squ]25 c = 5