 #1
 47
 1
Dear Forum,
I am not sure how I can calculate the Qfactor in the circuit attached.
(The circuitresonates at 13.56MHz and tuned to 50 ohm input impedance, thus the two capacitors)
Is the Qfactor of the circuit simply [tex]Q = \frac{\omega L}{R_{a}+R_{coil}}[/tex] ?
I went through some examples and it looks like this is the right way to do it, however, I´m not sure why the capacitorscan be disregarded, since they also store reactive energy.
best regards
eirik
I am not sure how I can calculate the Qfactor in the circuit attached.
(The circuitresonates at 13.56MHz and tuned to 50 ohm input impedance, thus the two capacitors)
Is the Qfactor of the circuit simply [tex]Q = \frac{\omega L}{R_{a}+R_{coil}}[/tex] ?
I went through some examples and it looks like this is the right way to do it, however, I´m not sure why the capacitorscan be disregarded, since they also store reactive energy.
best regards
eirik
Attachments

7.1 KB Views: 384