- #1

temujin

- 47

- 1

Dear Forum,

I am not sure how I can calculate the Q-factor in the circuit attached.

(The circuitresonates at 13.56MHz and tuned to 50 ohm input impedance, thus the two capacitors)

Is the Q-factor of the circuit simply [tex]Q = \frac{\omega L}{R_{a}+R_{coil}}[/tex] ?

I went through some examples and it looks like this is the right way to do it, however, I´m not sure why the capacitorscan be disregarded, since they also store reactive energy.

best regards

eirik

I am not sure how I can calculate the Q-factor in the circuit attached.

(The circuitresonates at 13.56MHz and tuned to 50 ohm input impedance, thus the two capacitors)

Is the Q-factor of the circuit simply [tex]Q = \frac{\omega L}{R_{a}+R_{coil}}[/tex] ?

I went through some examples and it looks like this is the right way to do it, however, I´m not sure why the capacitorscan be disregarded, since they also store reactive energy.

best regards

eirik