# Q Find the curve whose polar subtangent is constant

1. Jun 22, 2005

### himanshu121

I have done this thing::
$$\frac{rsin(\theta)}{k}= - \frac{r+tan(\theta) \frac{dr}{d\theta}}{-rtan\theta + \frac{dr}{d\theta}}$$

Rearranging and solving i got

$$rsin \theta \frac{d(rcos\theta)}{d\theta}=-k\frac{d(rsin\theta)}{d\theta}$$

on further solving i got
$$rcos\theta= -kln(rsin\theta) +c$$

But the answer at the back is ::
:: The Reciprocal Spiral ::
:: r(\theta - \alpha) = c::

Where I went wrong ::Pls Help