Q of p+p reaction.

  • Thread starter Ene Dene
  • Start date
  • #1
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p+p -> deutron+positron+neutrino(e)

The question is how much energy is released?

[tex]Q=(m_{p}+m_{p})-(m_{d}+m_{e^+}+0.26MeV)=(938+938)MeV-(938+939+0.51+0.26)MeV<0[/tex]

So I don't understand how can energy be relesed? I found that Q for that reaction is 1.442MeV. What am I doing wrong?
 

Answers and Replies

  • #2
Hootenanny
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Note that md < mp + mn
 
  • #3
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What is the mass of deutron then? How can I calculate it, or where can I find that data?
 
  • #4
malawi_glenn
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You should have data in your course book, and also in tables that you may use on exams etc. Here is some good internet rescourses:

http://nucleardata.nuclear.lu.se/database/masses/ [Broken]

The mass of the deutron is [tex] m_n + m_p - E_{Binding} [/tex]
 
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  • #5
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Thank you.
 

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