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Q versus q in Coulomb's Law

  1. May 28, 2014 #1
    1. The problem statement, all variables and given/known data

    This is a question about notation. When working with Coulomb's Law, is Q>0 and q<0? What is the difference between Q and q?

    2. Relevant equations

    n/a

    3. The attempt at a solution
    n/a
     
  2. jcsd
  3. May 28, 2014 #2
    My understanding is that they are just "different" charges. They may both be negative or both positive or one is positive and one is negative.
     
  4. May 28, 2014 #3
    With subscripts to denote which charge is which, I do not understand why Q and q are used. I will check with my professor tomorrow. Thanks for your response.
     
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