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Q vxB magnetic force

  1. Jun 21, 2013 #1
    there is something I don't understand
    maybe someone can tell me

    - a charge q has velocity v along the x axis
    - there is a uniform magnetic field B along the y axis
    - so the particule experience a force F=qvB along the z axis

    Now consider the same situation in a reference frame moving at velocity v along the x axis.
    Now F=qvB=0 and there is no force on the particule.

    What am I missing?
    How to reconcile those situation?
  2. jcsd
  3. Jun 21, 2013 #2

    Simon Bridge

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