Can We Measure the Weak Nuclear Fine Structure Constant via Beta Decay?

In summary, the weak nuclear fine structure constant, also known as the Fermi coupling constant, can be measured through the process of beta decay. This constant is a fundamental parameter in the standard model of particle physics and determines the strength of the weak nuclear force. By studying the decay rates of beta particles, scientists can obtain precise measurements of this constant and further our understanding of the fundamental forces of the universe.
  • #1
Orion1
973
3

Penning trap upper limit for the electron particle radius:
[tex]r_e \leq 10^{-22} \; \text{m}[/tex]

QED Compton wavelength electron radius:
[tex]\boxed{r_e = \alpha_e \overline{\lambda}_c}[/tex]

QED Compton electron radius:
[tex]\boxed{r_e = \frac{\hbar \alpha_e}{m_e c}}[/tex]

QED electron fine structure constant:
[tex]\alpha_e = \frac{r_e}{\overline{\lambda}}_c = \frac{m_e c r_e}{\hbar}[/tex]

[tex]\boxed{\alpha_e = \frac{m_e c r_e}{\hbar}}[/tex]

Weak nuclear fine structure constant:
[tex]\alpha_w = \sqrt{ \frac{T_{\Delta}}{T_{\Sigma}}} = 2.738 \cdot 10^{-7}[/tex]
[tex]T[/tex] - Delta and Sigma particle lifetimes

[tex]\boxed{\alpha_e = 2.589 \cdot 10^{-10}}[/tex]
[tex]\boxed{\alpha_w = 2.738 \cdot 10^{-7}}[/tex]

The QED electron fine structure constant magnitude corresponds with the weak nuclear fine structure constant.

How is [tex]\alpha_w[/tex] measured via weak [tex]\beta[/tex] decay?

Are these equations correct?

Reference:
http://en.wikipedia.org/wiki/Electron#Fundamental_properties"
http://en.wikipedia.org/wiki/Weak_nuclear_force"
http://hyperphysics.phy-astr.gsu.edu/HBASE/forces/couple.html#c4"
http://hyperphysics.phy-astr.gsu.edu/HBASE/particles/weastr.html#c1"
 
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  • #2
what do you want?
 
  • #3
Orion1 said:
Weak nuclear fine structure constant:
[tex]\alpha_w = \sqrt{ \frac{T_{\Delta}}{T_{\Sigma}}} = 2.738 \cdot 10^{-7}[/tex]

No, it's not. It's [itex]\alpha/\sin^2\theta_w[/itex].

Orion1 said:
According to QED, the electron is defined by the Weak nuclear force.

No, it's not. That doesn't even make any sense, as QED doesn't know anything about the weak nuclear force.
 
  • #4
Vanadium 50 said:
It's [itex]\alpha/\sin^2\theta_w[/itex].

Vanadium, that is an element, not an equation.

Is this the equation that you attempted to define?

Weak nuclear fine structure constant:
[tex]\alpha_w = \frac{\alpha}{\sin^2 \theta_w}[/tex]
[tex]\theta_w[/tex] - Weinberg angle (weak mixing angle)

Please state the numerical value for that solution and cite a reference.

Have you examined my references in post #1?

Why is the university level hyperphysics weak nuclear fine structure constant equation incorrect?

Reference:
http://en.wikipedia.org/wiki/Weinberg_angle"
 
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  • #5
Orion1 said:

Vanadium, please state the numerical value for that solution and cite a reference.

Look in mandl's textbook in Quantum Field theory for instance. Or any book that contains the gauge theory of the electroweak unification.

Also, what is the purpose of your original post? Are you asking something?
 
  • #6
malawi_glenn said:
Also, what is the purpose of your original post? Are you asking something?

Have you examined my references in post #1?

Are my equations listed in post #1 correct?

Anyone have mandl's textbook in Quantum Field Theory? :smile:
 
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  • #7
Orion1 said:

Are my equations listed in post#1 correct?

as Vanadium pointed out, no.

The QED fine structure constant is 1/137

why are you doing all this?

A good, easy, reference on this, I consider particle physics by Martin

And yes, Manls textbook on QFT is quite common to have... your Library should definitely have one copy. Otherwise, there should be millions of tutorials on www, try search for "Antonio Pich" on ArXiV

Your references in post 1 is wikipedia and hyperphysics, what should I say?... they are not rigour
 
  • #8
malawi_glenn said:
as Vanadium pointed out, no.

Vanadium only stated one equation as incorrect. You are now stating all the equations are incorrect? Including the university level hyperphysics equations?

malawi_glenn said:
The QED fine structure constant is 1/137

Negative, that value for [tex]\alpha[/tex] is not 'rigorous'.

malawi_glenn, you are unable to state a numerical value for Mandl and Martin's [tex]\alpha_w[/tex].

rig·or·ous:
. precise
. severely accurate

malawi_glenn, based upon the 'incorrect' equations in post #1, what is the numerical value for the electron radius if the QED fine structure constant for electromagnetism is used?

And why exactly do all these equations fail dimensional examination?
 
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  • #9
why would anyone use "electron radius" since it is not a 'real' concept, just a unit?

ok, the fine structure constant is 1/137.03599907 which is a numerical value of 2.39934 e-4If you want to define a constant which has the units of length by introducing [tex]
r_e = \alpha \lambda_r
[/tex] you are free to do it, it is just a unit, nothing 'physical'

The relation between 'the classical electron radius' and the electron comptonwavelngth is: [tex]r_e{\text{ }}_{class} = {\alpha \lambda_e \over 2\pi} = \alpha^2 a_0 [/tex]

where a_0 is the bohr radius.

The weak 'fine structure' constant is [itex] \alpha _W \approx 0.58\alpha [/itex] (martin)

in QED, the electron is a point-particle, so don't call it "QED electron radius"..
 
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  • #10
malawi_glenn said:
as Vanadium pointed out, no.

And why exactly do all these equations fail dimensional examination?

malawi_glenn said:
in QED, the electron is a point-particle.
The Penning trap experiment that determined the electron radius upper limit considers the electron as a QED point-particle.

malawi_glenn, then by your own supposition:
[tex]\alpha_w = \frac{\alpha}{\sin^2 \theta_w} = 0.58 \cdot \alpha = 4.232 \cdot 10^{-3}[/tex]

A rigorously determined value: (Martin)
[tex]\alpha_w = 4.232 \cdot 10^{-3}[/tex]

Is this equation correct?

malawi_glenn, based upon the 'incorrect' equations in post #1 and post #9, what is the numerical value for the electron radius if the QED fine structure constant for electromagnetism is used?

Reference:
http://en.wikipedia.org/wiki/Penning_trap"
 
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  • #11
because physics is more advanced then this...

e.g. the bohr radius is just a unit, it is not an orbital radius of the electron in hydrogen (as we know, the radial distance in hydrogen is a probabilistic quantity)

the number 1/137 is more rigour than your [tex]
\boxed{\alpha_e = 2.589 \cdot 10^{-10}}
[/tex] ... rigour in that sense that it is close to the experimental measured value.

I mean, what is the physical (first principle reason) for someone to suggest that the electron radius is alpha time electron Compton wavelength? What is the underlying idea?
 
  • #12
malawi_glenn said:
I mean, what is the physical (first principle reason) for someone to suggest that the electron radius is alpha time electron Compton wavelength? What is the underlying idea?


malawi_glenn, based upon the 'incorrect' equations in post #1 and post #9, what is the numerical value for the electron radius if the QED fine structure constant for electromagnetism is used?

And why exactly do all these equations fail dimensional examination?
 
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  • #13
you don't have a calculator or what?

and "what" electron radius? There are many kinds of electron radii units, you mean your suggestion [tex]
\boxed{r_e = \alpha_e \overline{\lambda}_c}
[/tex]? Which you call "QED compton wavelenght radius"?
 
  • #14
malawi_glenn said:
Which you call "QED Compton wavelength electron radius"?

[tex]\boxed{r_e = \alpha_e \overline{\lambda}_c}[/tex]

Affirmative.

malawi_glenn, you still have not stated why exactly do all these equations fail dimensional examination?

malawi_glenn said:
The QED fine structure constant is 1/137
Negative, that value for [tex]\alpha[/tex] is numerology and not 'rigorous' at all.

malawi_glenn said:
the fine structure constant is . . . a numerical value of 2.39934 e-4. Rigour in that sense that it is close to the experimental measured value.
Negative, that numerical value is incorrect, and certainly not even close to rigorous.

malawi_glenn, what are the physical (first principle reasons) for these equations?

Classical electron radius:
[tex]r_e =\frac{\alpha \lambda_e}{2 \pi}[/tex]

Rigorous classical electron radius:
[tex]r_e = \frac{1}{4 \pi \epsilon_0} \frac{e^2}{m_e c^2} = 2.8179402894(58) \cdot 10^{-15} \; \text{m}[/tex]

malawi_glenn said:
Your references in post 1 is wikipedia and hyperphysics, what should I say?... they are not rigour

Negative, the numerical value for the classical electron radius from Wikipedia is excellent, they are both extremely rigorous.

malawi_glenn said:
1/137, 2.39934 e-4, you don't have a calculator or what?
Negative, I do not believe that I am the one that requires a calculator at the moment.

Reference:
http://en.wikipedia.org/wiki/Classical_electron_radius"
 
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  • #15
Orion1 said:

Affirmative.

roger copral
 
  • #16
Orion1 said:
Negative, that value for [tex]\alpha[/tex] is numerology and not 'rigorous' at all.

Negative, that numerical value is incorrect, and certainly not even close to rigorous.

What in blazes are you talking about?
 
  • #17
Vanadium 50 said:
What in blazes are you talking about?

Only God knows... he usally does this kind of approach =/

1/137 is not rigour, it is just "numerology" LOL
 
  • #18
Vanadium_50 said:
What in blazes are you talking about?
malawi_glenn said:
the fine structure constant is . . . a numerical value of 2.39934 e-4

malawi_glenn's numerical value for the electromagnetic fine structure constant is incorrect.

malawi_glenn, you still have not stated a correct numerical value for the electromagnetic fine structure constant.

Vanadium_50, why is the university level hyperphysics weak nuclear fine structure constant equation incorrect?

Vanadium_50, and why exactly do all these equations fail dimensional examination?

Vanadium_50, is the equation and numerical values correct in post #10?

Reference:
https://www.physicsforums.com/showpost.php?p=2123562&postcount=10"
 
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  • #19
orion, in post #9 I gave you a better (closer to experimental) value of alpha (1/137 is a VERY good number for alpha, orion you are a pain in our *** with your style..

the figure 2.39934 e-4 is of course wrong, i made that on purpose LOL, why can't you just take 1/137.03599907 in your own calculator??

This is an open forum, I can answer to anything I want to.

Why do you want to calculate all this crap anyway?

The value hyperphysics gives you for the weak finestructure is just an approximation, the hadrons are composite objects etc, you have to go to elementary particle level to examine the couplings of interactions. If you want the latest values, go to particle data group, not wikipedia or hyperphysics.

You are the one who proposed that a unit called "QED electron radius" should be invented, you have to motivate "why". I am not the guy who should say on what first principles it relies on.

The classical electron radius is something which you evaluate from classical electrodynamics, when you evaluate Thomson scattering etc. It should be done in great detail in e.g. Jackson.

I now invent a thing called "Glenn electron radius"

[tex]r_e^{\text{Glenn}} = \alpha_e^3 \frac{1}{4\pi\epsilon_0}\frac{e^2}{m_e c^2}[/tex]

And what does it mean? I have no idea, it is just a unit.

You see my point why all your 'effort' is pointless?
 
  • #20
malawi_glenn said:
I now invent a thing called "Glenn electron radius"
[tex]r_e^{\text{Glenn}} = \alpha_e^3 \frac{1}{4 \pi \epsilon_0} \frac{e^2}{m_e c^2}[/tex]

Negative, that equation is dimensionally incorrect.

hyperphysics gives you for the weak fine structure is just an approximation.
An accurately measured approximation is not a failure in dimensional examination.

malawi_glenn, instead of deliberately introducing known unbalanced and non-formulated dimensionally incorrect equations on this forum without any referencing at all, why not state exactly why do all these equations fail dimensional examination?

malawi_glenn, you have not stated what 'first principle' the classical electron radius is based upon.

Classical electron radius:
[tex]r_e = \frac{1}{4 \pi \epsilon_0} \frac{e^2}{m_e c^2}[/tex]

[tex]\boxed{\frac{e^2}{4 \pi \epsilon_0} = \hbar c \alpha}[/tex]

[tex]r_e = \frac{1}{4 \pi \epsilon_0} \frac{e^2}{m_e c^2} = \frac{\hbar \alpha}{m_e c} = \alpha \overline{\lambda}_c[/tex]

Electromagnetic fine structure constant:
[tex]\boxed{\alpha = \frac{e^2}{4 \pi \epsilon_0 \hbar c}} = 7.2973525705 \cdot 10^{-3}[/tex]

[tex]\boxed{\alpha = 7.2973525705 \cdot 10^{-3}}[/tex]

QED Compton wavelength electron radius:
[tex]\boxed{r_e = \alpha \overline{\lambda}_c}[/tex]

Reference:
http://en.wikipedia.org/wiki/Fine-structure_constant"
http://en.wikipedia.org/wiki/Classical_electron_radius"
 
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  • #21
that is because I am using "Glenn units" on the electric charge so that [tex] r_e^{\text{Glenn}} [/tex] get the unit of length.

I did not name it after myself... the name is from Glenn Strömberg, a great soccer player.

The reason for why just some dimensional analysis and puzzling is pointless is the amount of arbitrariness.

You consider the thing called "QED compton wavelength radius"
[tex]
\boxed{r_e = \alpha \overline{\lambda}_c}
[/tex]

Now WHAT do you want to achieve/describe with that? It is just a unit, with dimensions of length.

I can invent infinite number of those, by just multiplying a quantity without dimensions

Questions:

1) What do you want to achieve with this? What is the physical meaning of "QED Compton wavelength electron radius"? Why do you call it QED.. when it has nothing to do with QED at all? You "cooked" the unit you have by multiplying the electron compton wavelenght with the fine structure constant, why?

2) Do you know where the units "electron compton wavelenght" and "Classical electron radius" come from and aware of what they mean and have the names which they have?

The first principle physics behind the unit "classic electron radius" can, as I said, be found in references like Jackson or just google it. I don't have to give you a clash course in classic electrodynamics here.
 
  • #22
Thread locked pending Moderator review.
 

1. What is the weak nuclear fine structure constant?

The weak nuclear fine structure constant, denoted by αw, is a fundamental constant in particle physics that describes the strength of the weak nuclear force. It is a dimensionless parameter that is approximately equal to 1/137.

2. How is the weak nuclear fine structure constant related to beta decay?

Beta decay is a type of nuclear decay that involves the emission of a beta particle (either an electron or a positron) from an unstable nucleus. The probability of beta decay occurring is directly related to the weak nuclear fine structure constant, as it is a measure of the strength of the weak force responsible for the decay process.

3. Can we accurately measure the weak nuclear fine structure constant via beta decay?

Yes, it is possible to measure the weak nuclear fine structure constant through beta decay experiments. However, due to the complex nature of beta decay and the limitations of current technology, the accuracy of these measurements is still relatively low compared to other fundamental constants.

4. What techniques are used to measure the weak nuclear fine structure constant via beta decay?

There are several techniques that have been used to measure the weak nuclear fine structure constant via beta decay, including precision spectroscopy, precision counting of decay events, and measuring the energy spectrum of beta particles emitted from decaying nuclei.

5. What is the significance of accurately measuring the weak nuclear fine structure constant?

Accurately measuring the weak nuclear fine structure constant is important for understanding the fundamental forces that govern the behavior of matter at the subatomic level. It also has implications for other areas of physics, such as cosmology and the search for new particles beyond the standard model.

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