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Qed, Qcd

  1. Jan 27, 2004 #1
    Sqed, Sqcd...



    Strong Nuclear Quantum Chromodynamics: (SQCD)
    [tex]\alpha_s \left( E \right) = \frac{12 \pi}{ \left(33 - 2N_f \right) ln \left[ \frac{E^2}{\Lambda^2} \right]}[/tex]

    Strong Nuclear Quantum Electrodynamics: (SQED)
    [tex]\alpha_s \left( q^2 \right) = \frac{ \alpha_s ( q_0^2) }{1 - \left( \frac{\alpha_s (q_0^2) }{3 \pi} \right) ln \left[ \frac{q^2}{m^2} \right] }[/tex]

    [tex]\alpha_s \left( q^2 \right) = \alpha_s \left( E \right)[/tex]

    [tex]\alpha_s \left( q^2,E \right) = \frac{ \alpha_s ( q_0^2) }{1 - \left( \frac{\alpha_s (q_0^2) }{3 \pi} \right) ln \left[ \frac{q^2}{m^2} \right] } = \frac{12 \pi}{ \left(33 - 2N_f \right) ln \left[ \frac{E^2}{\Lambda^2} \right]}[/tex]

    SQCD, SQED Equasion Normalization:
    [tex]\alpha_s (q_0^2)(33 - 2N_f) ln \left[ \frac{E^2}{\Lambda^2} \right] = 12 \pi \left( 1 - \frac{\alpha_s (q_0^2)}{3 \pi} ln \left[ \frac{q^2}{m^2} \right] \right)[/tex]

    [tex]\Lambda[/tex] = 0.2 Gev - experimentally determined value
    Nf - quark flavour number (16 max.)
    q0 - strong nuclear charge

    Effectivity?

     
    Last edited: Jan 27, 2004
  2. jcsd
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