Can the energy flux of an EM wave be represented by a single photon?

In summary, the electric and magnetic fields are described in terms of photon exchange. However, if a photon itself is made of electric and magnetic fields, a paradox to an ill-informed brain.
  • #1
jaydnul
558
15
I might be asking a question who's answer is way beyond my level but ill give it a shot. In QED, an electric or magnetic field is described in terms of exchanged photons, right? But if a photon itself is made of electric and magnetic fields... a paradox to my ill-informed brain. :mad:
 
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  • #2
You're just confusing the things you have read!
Electromagnetic field is somehow a way of saying how many photons you can find on average in a region of space.
And electromagnetic force between two charged particles is described as a process of photon exchange.
Although I think there should be more to it which I don't know,so I hope people more familiar with QED will answer too.
 
  • #3
Jd0g33 said:
I might be asking a question who's answer is way beyond my level but ill give it a shot. In QED, an electric or magnetic field is described in terms of exchanged photons, right? But if a photon itself is made of electric and magnetic fields... a paradox to my ill-informed brain. :mad:

Particles are vibrations in quantum fields. The fundamental "stuff" is the quantum field.

Imagine a vacuum, a complete empty space, maybe far out in space somewhere. This empty space is still filled with quantum fields. That is a quantum field for photons, one for the electrons, one for the quarks, one for the Higgs particles, one for each fundamental particle.

In vacuum all these quantum fields are not excited, but due their quantum nature are not completely still either, they vibrate very little by themselves. But the strength of E-M field in vacuum on average is zero.

When you interact with a quantum field, e.g. move two electric charged bodies in the vacuum, you excite a quantum field above its vacuum state. Depending on how long-lived these excitations/ vibrations are, you call them particles.

So always, when you through interaction excite/ vibrate a quantum field, in vacuum or not, and these excitations exist long enough in space and time to be measured, you have particles.
 
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  • #4
Hmm, that's very interesting. Is there any Wikipedia page I could read that would tell me more about the quantum field? Is that QED?

So is the classical view of an electromagnetic wave incorrect? If a photon is modeled as a point particle in the standard model, then it isn't composed of anything, it's just a fluctuation in the quantum field. On the other hand, classical physics says it is composed of oscillating magnetic and electric fields. But magnetic and electric fields are the exchange of photons. So is the classical view of a photon, the oscillating electromagnetic fields, only correct if you look at "wave" of light? (much more than just one photon)
 
  • #5
You can read more about QED here.

To describe electromagnetic field QED is using the electromagnetic four-potential Aμ. The classical electric and magnetic fields can be calculated from the four-potential Aμ: see for example here (page 332 onwards).

Photon is an excitation of the quantized field. After the quantization the electromagnetic field is no longer classical and things get tricky: the field turns into operator which means it does not have a definite value at each point in space, but is rather in a quantum superposition of many configurations.

I am not sure what you mean by "classical view of a photon", because photons are quantum objects and do not make sense classically.
 
  • #6
Maybe this is a better way to pose my question. Hertz discovered the electromagnetic wave with a loop of conductive material and a tiny gap in which there would be spark from the induced current by the EM wave passing through the loop. If this experiment was done, but the EM wave consisted of just one single photon, would it still have the same effects, inducing a current in the conductor? (Although very very very small). Or is it the interaction of many photons that creates the phenomena of oscillating E&M fields that are both perpendicular to the direction traveled (this is what I mean by "classical view")?
 
  • #7
Yes, a single photon would produce a current. In fact, in leading order in time-dependent perturbation theory, emission or absorption of a single photon is equivalent to a classical EM wave of a certain amplitude (which depends on the initial and final states of the stuff emitting/absorbing the photon). It is for this reason that classical EM can be a useful approximation even in situations involving just one photon.
 
  • #8
Jd0g33 said:
Maybe this is a better way to pose my question. Hertz discovered the electromagnetic wave with a loop of conductive material and a tiny gap in which there would be spark from the induced current by the EM wave passing through the loop. If this experiment was done, but the EM wave consisted of just one single photon, would it still have the same effects, inducing a current in the conductor? (Although very very very small). Or is it the interaction of many photons that creates the phenomena of oscillating E&M fields that are both perpendicular to the direction traveled (this is what I mean by "classical view")?

Of course doing Hertz's experiment with such a weak field won't have the same results that Hertz got.The point is,classical electromagnetism can be derived by getting averages of QED equations on a very large number of photons and on long enough time scales and and distances.
The energy flux([itex]\frac{J}{s m^2} [/itex])of an EM wave is represented by its Poynting vector [itex] \vec{S}=\vec{E}\times\vec{H} [/itex].
Now let's calculate the energy flux of a number of photons moving in a vacuum in the direction [itex] \hat{k} [/itex].Their velocity is c and let's call their number density n and if we consider a monochromatic wave with frequency [itex] \omega [/itex],then the energy flux becomes [itex] \vec{S}=n\hbar\omega c \hat{k} [/itex]
So we have: [itex] \vec{E}\times\vec{H}=n\hbar\omega c \hat{k} [/itex].
Let's simplify the matter by assuming that [itex] \vec{E} [/itex] and [itex] \vec{H}[/itex] are perpendicular to each other so,using [itex] H=\frac{E}{\mu_0 c} [/itex] we may write [itex] E=c\sqrt{n\hbar\omega \mu_0} [/itex]
I don't know,maybe some people don't like it,and it may seem not so useful,but I think it can help for getting some insight.
 

1. What is QED and how does it relate to the exchange of photons?

QED stands for Quantum Electrodynamics, and it is the quantum field theory that describes the interactions between charged particles and electromagnetic fields. The exchange of photons is a fundamental process in QED, where particles emit and absorb virtual photons to interact with each other.

2. What is the significance of the exchange of photons in QED?

The exchange of photons is essential in QED because it is the mechanism through which charged particles interact with each other. This process allows for the creation and annihilation of particles, as well as the scattering and absorption of photons. Without the exchange of photons, many phenomena in the quantum world would not be possible.

3. How does QED explain the behavior of light?

QED explains the behavior of light as both a wave and a particle. The theory describes light as a stream of particles called photons, which interact with charged particles. These interactions can cause the photons to behave like a wave, exhibiting interference and diffraction patterns.

4. Can QED be applied to other fundamental forces besides electromagnetism?

Yes, QED is a part of the Standard Model of particle physics, which includes the other fundamental forces of nature: strong nuclear force, weak nuclear force, and gravity. While QED specifically deals with electromagnetism, the principles of quantum field theory can be applied to these other forces as well.

5. How has QED been experimentally verified?

QED has been experimentally verified through numerous experiments, including precision measurements of the electron's magnetic moment and the Lamb shift in atomic energy levels. The predictions of QED have also been confirmed by particle accelerators, such as the Large Hadron Collider. Overall, QED has been one of the most successful and accurate theories in physics.

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