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## Main Question or Discussion Point

I have been working through Srednicki this summer to teach myself qft, and all too often I've gotten stuck on a small point and ended up spending a great deal of time clearing it up by myself. While this is probably an important part of the learning process, I am progressing a bit too slowly, so I thought I would post some of the questions I have here if anyone is willing to help me out. Please forgive me in advance if any of the questions are overly simple or stupid.

To start with, I'm stuck in section 39 on working out the anti-commutation relations for the creation and annihilation operators. For example, take the calculation at the top of pg 246 (eq 39.16)

[itex]

$\{b_s(\textbf{p}),b_{s'}^{\dag}(\textbf{p}')\} = \int d^3xd^3ye^{-ipx+ip'y}\{\overline{u}_s(\textbf{p})\gamma^0\Psi(x),\overline{\Psi}(y)\gamma^0u_{s'}(\textbf{p}')\}$\\

$=\int d^3xd^3y e^{-ipx+ip'y}\overline{u}_s(\textbf{p})\gamma^0\{\Psi(x),\overline{\Psi}(y)\}\gamma^0u_{s'}(\textbf{p}')$

[/itex]

Srednicki starts with the second line, but how does that follow from the first line that I have written?

To start with, I'm stuck in section 39 on working out the anti-commutation relations for the creation and annihilation operators. For example, take the calculation at the top of pg 246 (eq 39.16)

[itex]

$\{b_s(\textbf{p}),b_{s'}^{\dag}(\textbf{p}')\} = \int d^3xd^3ye^{-ipx+ip'y}\{\overline{u}_s(\textbf{p})\gamma^0\Psi(x),\overline{\Psi}(y)\gamma^0u_{s'}(\textbf{p}')\}$\\

$=\int d^3xd^3y e^{-ipx+ip'y}\overline{u}_s(\textbf{p})\gamma^0\{\Psi(x),\overline{\Psi}(y)\}\gamma^0u_{s'}(\textbf{p}')$

[/itex]

Srednicki starts with the second line, but how does that follow from the first line that I have written?