Beware: The average of the squares, [itex]\langle j^2 \rangle[/itex], is not equal, in general, to the square of the average, [itex]\langle j \rangle ^2[/itex]
This tells you very explicitly what the interpretation of both quantities should be.
#3
g.lemaitre
267
1
I didn't see that sentence the square of the average is not the same as the average of squares. But now i do.
#4
g.lemaitre
267
1
Nevertheless I'm truly amazed that you saw the question almost the moment I posted it and answered it in about 5 seconds. Wow!
so the <j^2> means the average of the squares of j values
and <j>^2 is the square of the average of j values
#6
g.lemaitre
267
1
But I guess what the brackets mean is that you have the take the average of what is between them, so pretend { is a bracket. If you know the latex for brackets please let me know.
{j^2} where j is 2,3,4 would be the average of 4 9 16 hence a little above 9 whereas {j}^2 would be 9 exactly, right?
#7
Muphrid
834
2
Use \langle and \rangle for pretty brackets (not horrendously bad ones, which are what <> give you).
Otherwise, yes, you have the basic idea now. You should be accustomed to seeing [itex]\langle j^2 \rangle - \langle j \rangle^2 = \sigma_j^2[/itex] as well. This is one formula for the variance.