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Quadratic air resistance clarification
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[QUOTE="Mark44, post: 6403201, member: 147785"] You don't include a constant of integration in a definite integral. Your question is not very clear. By "why does the sign change..." I assume, but don't know for certain, that you are asking about why arctan shows up with a negative sign in the integral right after the first one in red. The reason is that v = 0 and v[SUB]0[/SUB] is some positive number. So you evaluate the result expression at v = 0, and then subtract the value when v = v[SUB]0[/SUB]. t in the problem is the time when the projectile gets to the top of its path. [/QUOTE]
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Quadratic air resistance clarification
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