Solve Quadratic Equation (x³-4x²+5x-2):(x-1)= x²- 2x-8 | Need Help?

In summary: So, when we say that x-1 divides into x3- 3x2+ 6x- 8 exactly x2-2x- 8 times, what we really mean is that x-1 divides into x3- 3x2+ 6x- 8 exactly three times, and then it doesn't divide any further.
  • #1
lion89
1
0
here is my task: (x³-4x²+5x-2):(x-1)=
We did such task in school but I didn't got it ..

Here is the task that we did in school
(x³-3x²-6x+8) :(x-1)= x²- 2x-8 but I don`t get it why x² is the result and why 3x² ??
Can someone help me? Thank you in advance
 
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  • #2
Regular polynomial division is easier than standard long division with pure constants. Your approach should be exactly the same.

Ask this: What is x^3 divided by x ? It is certainly not three times anything. You have no reason for coming to 3*x^2.
 
  • #3
To expand on symbolipoint's response, suppose you were asked to divide 3524232 by 83. You would start by noting that 8 divides into 35 for times so the first digit of the quotient is (probably) 4. you need the "probably" because the digit after the 8 might cause a problem. But in this case 4*83= 329 and 352- 329= 23, less than 83. So you subtract those and your problem becomes 234232 divided by 81. 8 will divide into 23 twice (3*8= 24 so 3 times doesn't quite fit). 2*83= 163 and 234- 163= 71. You know that the first two digits of the quotient are 42.. and you continue.

x3- 3x2- 6x- 8 divided by x-1 is much the same thing- the "x" just represents a number so all the rules of algebra apply. x divides into x3 x3/x= x2[/sup times so we try x2 as the divisor: x2 times x-1 is x3- x2 and x3- 3x2 minus x3- x2 is -3x2- (-x[sup[2)= -2x2. Of course, the x3 terms cancel- that was the whole point of choosing the divisor to be x2. We now have left -2x2- 6x+ 8 to be divided by x- 1.

x2 will divide into -2x2 -2x times, so we try -2x as the next term in the quotient: -2x times x- 1 is -2x2+ 2x and -2x2- 6x minus -2x2+ 2x is just -6x-(2x)= -8x. We have left -8x+ 8 to be divided by x- 1.

Okay, -8x divided by x is, of course, -8 and -8 times x-1 is -8+ 8, exactly what we had left: x-1 divides into -8x+ 8 exactly -8 times. Putting all of that together, x-1 divides into x3- 3x2+ 6x- 8 exactly x2-2x -8 times.

Now, you try exactly the same thing with x3- 4x2+ 5x- 2 divided by x-1. Warning: even when you are dividing numbers, divisions don't always come out even: 33 divided by 4 is 8 with a remainder of 1 (or 8+ 1/4).
 

What is a quadratic equation?

A quadratic equation is a polynomial equation of the second degree, meaning it contains a variable raised to the power of two. The standard form of a quadratic equation is ax^2 + bx + c = 0, where a, b, and c are constants and x is the variable.

How do you solve a quadratic equation?

There are several methods for solving a quadratic equation, including factoring, completing the square, and using the quadratic formula. The method used will depend on the specific equation and what is most efficient for solving it.

What is the quadratic formula?

The quadratic formula is a formula used to solve any quadratic equation. It is written as x = (-b ± √(b^2 - 4ac)) / 2a, where a, b, and c are the constants in the quadratic equation. This formula can be derived from completing the square on the standard form of a quadratic equation.

Why are quadratic equations important?

Quadratic equations are important in many fields, including mathematics, physics, engineering, and economics. They can be used to model real-world situations and make predictions. They also have numerous applications in calculus, such as finding the maximum or minimum value of a function.

What are the roots of a quadratic equation?

The roots of a quadratic equation are the values of x that make the equation true. Graphically, they represent the x-intercepts of the parabola formed by the equation. Algebraically, they can be found by solving the equation using one of the methods mentioned above.

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