- #1

Madhav Goel

- 3

- 0

## Homework Statement

3x^2 + px + 3 = 0, p>0, one root is square of the other, then p=?? [/B]

## Homework Equations

sum of roots = -(coefficient of x)/(coefficient of x^2)[/B]

product of roots= constant term/coeffecient of x^2

## The Attempt at a Solution

ROot 1 = a

root 2 = b

b=a^2

a.b= 3/3

a^3=1

a=1

a^2=b=1

a+b=-p/3=2

p=-6

Where did i go wrong??[/B]