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Quadratic equations

  1. Nov 16, 2009 #1
    Hey there!
    I just want to know that this problem
    (t-2)^2=36
    can be solved by squaring t-2 so we have the answer as t=8 ,-4
    but suppose if I rather do like this that I square root 36 and remove the power on t-2
    then

    or t- 2= 6
    or t=8
    here also i get the 8 result but i dont get the -4 one.
    But I think it isnt a wrong way to deal ,is it?:uhh:
    I would be very much happy for any help!!
     
  2. jcsd
  3. Nov 16, 2009 #2
    Hi 1/2"
    When you take the square root for both sides ,you are to take the absolute values when removing squares; that is t-2=6 or t-2=-6 so you will have
    t=8 , t=-4 as you get.
    Best regards
    Riad Zaidan
     
  4. Nov 16, 2009 #3

    Mark44

    Staff: Mentor

    Here's another way to look at this without absolute values.
    (t - 2)2 = 36
    <==> (t - 2)2 - 36 = 0
    <==> ((t - 2) - 6)((t - 2) + 6) = 0
    <==> (t - 8)(t + 4) = 0
    <==> t = 8 or t = -4
     
  5. Nov 16, 2009 #4
    Thanks a lot for helping !!:smile::smile:
     
  6. Nov 17, 2009 #5
    Hi Mark44 ,
    The problem was in ((removing squares)) from both sides by taking square roots and not in finding another way to solve the problem. In general, thanks a lot for you...........
    Best Regards
    Riad Zaidan
    Al-Quds Open University
     
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