- #1

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- 7

## Homework Statement

Given x^2 - xy + y^2 = 4(x+y-4) where x, y both are real then the number of pairs (x, y) satisfying the equation will be

(A) Only one

(B) Two

(C) Three

(D) No pair

## Homework Equations

## The Attempt at a Solution

The equation can be written as (x-2)^2 + (y-2)^2 + 8 = xy on opening the brackets and completing the square.

Beyond this, I really don't know what to do. Hit and trial doesn't seem to work very well either.