(adsbygoogle = window.adsbygoogle || []).push({}); Quadratic Question [Urgent]

The equation [tex]x^{2} + 2px + (3p + 4) = 0[/tex], where p is a postitve constant, has equal roots

Q) Find the value of p

Well if it has equal roots b² - 4ac = 0

so

(2p)² - 4(1)(3p + 4) = 0

4p² - 12p - 16 = 0

4(p² - 3p - 4) = 0

4((p+1)(p-4)) = 0

so the anwser is p = 16

BUT the question booklet says p = 4

Which is right???

Thx :)

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# Quadratic Question

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