1. May 14, 2006

Benny

Hi, can someone please help me out? I need to know if I can draw any conclusions from the following.

There is a quadrilateral such that two 'opposite' internal angles are 90 degrees. Is there anything that I can say about the line segment joining the two vertices of the quadrilateral which correspond to the other two internal angles? The 'other' vertices being the ones whose corresponding internal angle is not 90 degrees.

2. May 14, 2006

Curious3141

What exactly do you mean by opposite? Can you sketch a diagram? I had a post typed out before but your meaning is ambiguous so I deleted it.

3. May 14, 2006

Curious3141

In any case, the sum of the other two angles is 180 degrees.

And, if by opposite, you mean that the two angles have one forming side in common, then the figure becomes a trapezium.

4. May 14, 2006

Benny

I meant opposite as in the vertices I referred to were not formed by sides which are adjacent. Nevermind though, I figured out a way to do the problem I was working on without working using bisection of internal angles. Thanks anyway.

5. May 14, 2006

Gokul43201

Staff Emeritus