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logearav
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define quantisation? what answers fits to this question? folks please help.
Not really. For example, for a free quantum particle neither position nor energy or momentum takes a discrete spectrum. In fact, the word "quantization" is misleading and is used for historical reasons. Instead of talking about "quantum" theory perhaps it would be more correct to talk about "operator" theory, or "hilbert-space" theory, or "uncertainty" theory, as these expressions better (though not perfectly) express the main point of QM.da_willem said:Quantization refers to the discreteness of certain quantities (energy levels, angular momentum levels,..) in quantum theories.
Demystifier said:Not really. For example, for a free quantum particle neither position nor energy or momentum takes a discrete spectrum.
Haelfix said:Neither do most wavefunctions you can think off if you really want to be mathematically exact. Thats ok though, people have learned how to deal with that. Technically you have to expand the hilbert space (the trick to pass to its dual) such that various nice mathematical properties linking distributions and hilbert spaces are satisfied. We call this a Gelfland triple.
First, even if there are no free particles, there are at least particles for which (for practical purposes) the interaction can be neglected.masudr said:Demystifier:
There is no such thing as a free quantum particle; and furthermore, (as far as I know) the free planar wave does not exist in the space of square integrable functions.
Demystifier said:First, even if there are no free particles, there are at least particles for which (for practical purposes) the interaction can be neglected.
Second, you can work with wave packets that are square integrable superpositions of plane waves.
hyp said:hello james
pls explain me scattering matrix and t-matrix
hyp said:thanks james,
yes, I m now searching about phase shift with t-matriy for hyperon nucleon interaction. but now I got the problem in my code with this s-matrix.if say, I do not know exact error ,what can be?Now I know it can be s-matrix unitary violation.So could u explain me again about unitary violation in s-matrix.thanks in advance
Quantisation is the process of converting continuous data into discrete levels or categories. This is commonly used in fields such as physics, computer science, and digital signal processing.
Quantisation allows us to represent continuous data in a more manageable and efficient way. It also helps in reducing data storage and processing requirements, making it an important tool in various scientific and technological applications.
Some common examples of quantisation include converting analog audio signals into digital audio data, converting pixels in an image into discrete colors, and representing temperature data in degrees Celsius rather than its continuous values.
Quantisation is the process of converting continuous data into discrete levels, while discretisation is the process of dividing continuous data into smaller intervals. In other words, quantisation involves reducing the number of possible values, while discretisation involves dividing the range of values into smaller segments.
Quantisation can result in a loss of information and decrease in accuracy, as the continuous data is reduced to a smaller set of discrete levels. However, the level of accuracy depends on the number of quantisation levels used and the precision of the data being quantised.