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[tex]G^{-} = \psi_E \times \phi_E \cdot \psi_B \times \phi_B[/tex]

- Thread starter Antonio Lao
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- #1

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[tex]G^{-} = \psi_E \times \phi_E \cdot \psi_B \times \phi_B[/tex]

- #2

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[tex]G^{+} = - \psi_E \times \phi_E \cdot \psi_B \times \phi_B[/tex]

the interactions between graviton and antigraviton follow the rules:

[tex]G^{+}G^{-} = \alpha G^{-} [/tex]

[tex]G^{-}G^{-} = \beta G^{+} [/tex]

[tex]G^{+}G^{+} = \gamma G^{+} [/tex]

- #3

Janitor

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I note that your *G* has the unusual units of [tex]M^2 L^4 /T^2[/tex] if what you are calling a quantum of length has the anticipated unit of [tex]L[/tex] and if what you are calling a quantum of momentum has the anticipated unit of [tex]ML/T[/tex].

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- #4

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You are correct. The unit is proportional to the square of Planck's constant of action. This is a unit of double actions.Janitor said:I note that your G has the unusual units of ...

For the case of a time dependent structure, that is to say the time derivative of the linear momentum is not zero giving the existence of a force, the quanta are squares of energy.

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