The interatomic spring stiffness for magnesium is determined from Young's modulus measurements to be 12 N/m. The mass of one mole of magnesium is 0.012 kg. If we model a block of magnesium as a collection of atomic "oscillators" (masses on springs), what is one quantum of energy for one of these atomic oscillators? Note that since each oscillator is attached to two "springs", and each "spring" is half the length of the interatomic bond, the effective interatomic spring stiffness for one of these oscillators is 4 times the calculated value given above.(adsbygoogle = window.adsbygoogle || []).push({});

Use these precise values for the constants:

hbar= 1.054610e-34 J ยท s (Planck's constant divided by 2)

Avogadro's number = 6.022110e23 molecules/mole

k = 1.380710e-23 J/K (the Boltzmann constant)

I tried that one quantum of energy would be hbar*sqrt(ks/m) = 1.054e-34*sqrt((4*12)/(.012/6.02e23)) which is incorrect. The 'hint' is that one quantum of energy is the amount of energy required to raise one atomic oscillator from one energy level to the next highest energy level

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# Homework Help: Quantom of energy in Entropy

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