- #1

- 8

- 0

^{-10}m calculate the probability that the electron will be able to tunnel through the barrier.

Relevant equations= k = (sqrt(2m(V-E)) /h

-answer

(sqrt(2x9.1x10

^{-31}(13-8)x1.6x10

^{-19})x2pi all divided by h=(6.63x10

^{-34})

giving 1.14x10

^{10}??

then using e

^{-2kL}= e

^{-2x1.14x1010x5x10-10}

=11.2x10

^{-6}

is this right ??

and wat would the final answer be after the 11.2x10

^{-6}