Homework Help: Quantum-electron tunneling barrier

assuming that the electron has an incident energy of 8eV and that the barrier is of height Vo=13eV and width L=5x10^-10m calculate the probability that the electron will be able to tunnel through the barrier.


Relevant equations= k = (sqrt(2m(V-E)) /h


-answer

(sqrt(2x9.1x10^-31(13-8)x1.6x10^-19)x2pi all divided by h=(6.63x10^-34)

giving 1.14x10¹⁰??

then using e^-2kL = e^{-2x1.14x1010x5x10-10}

=11.2x10^-6

is this right ??
and wat would the final answer be after the 11.2x10^-6

 

erm i think we have yes
we've done a lot of electron tunnelling but not sure.