Quantum-electron tunneling barrier

Discostu19 · Jan 14, 2009

assuming that the electron has an incident energy of 8eV and that the barrier is of height Vo=13eV and width L=5x10^-10m calculate the probability that the electron will be able to tunnel through the barrier.

Relevant equations= k = (sqrt(2m(V-E)) /h

-answer

(sqrt(2x9.1x10^-31(13-8)x1.6x10^-19)x2pi all divided by h=(6.63x10^-34)

giving 1.14x10¹⁰??

then using e^-2kL = e^{-2x1.14x10¹⁰x5x10^-10}

=11.2x10^-6

is this right ??
and wat would the final answer be after the 11.2x10^-6

turin · Jan 15, 2009

Discostu19 said: ↑

assuming that the electron has an incident energy of 8eV and that the barrier is of height Vo=13eV and width L=5x10^-10m calculate the probability that the electron will be able to tunnel through the barrier.

Relevant equations= k = (sqrt(2m(V-E)) /h

-answer

(sqrt(2x9.1x10^-31(13-8)x1.6x10^-19)x2pi all divided by h=(6.63x10^-34)

giving 1.14x10¹⁰??

then using e^-2kL = e^{-2x1.14x10¹⁰x5x10^-10}

=11.2x10^-6

is this right ??

No. You need to compare the transmitted piece of the wavefunction to the incident piece of the wave function. Have you studied "scattering" yet? This is a 1-D scattering problem.

Discostu19 · Jan 16, 2009

erm i think we have yes
we've done a lot of electron tunnelling but not sure.

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Quantum-electron tunneling barrier

Discostu19

turin

Discostu19

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