assuming that the electron has an incident energy of 8eV and that the barrier is of height Vo=13eV and width L=5x10(adsbygoogle = window.adsbygoogle || []).push({}); ^{-10}m calculate the probability that the electron will be able to tunnel through the barrier.

Relevant equations= k = (sqrt(2m(V-E)) /h

-answer

(sqrt(2x9.1x10^{-31}(13-8)x1.6x10^{-19})x2pi all divided by h=(6.63x10^{-34})

giving 1.14x10^{10}??

then using e^{-2kL}= e^{-2x1.14x1010x5x10-10}

=11.2x10^{-6}

is this right ??

and wat would the final answer be after the 11.2x10^{-6}

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# Homework Help: Quantum-electron tunneling barrier

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