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## Homework Statement

Assume ψ(x,0)=e^(-λ*absvalue(x)) for x ± infinity, find Φ(k)

## Homework Equations

Φ(k)=1/√(2π)* ∫e

^{(-λ*absvalue(x))}e

^{(-i*k*x)}dx,-inf, inf[/B]

## The Attempt at a Solution

, my thought was Convert the absolute value to ± x depending on what of the number line was being integrated.[/B]U=i*k*x

du/(i*k)=dx

1/√(2π)*∫e

^{-λ*√(u2/(i*k)2)}*e

^{(-u)}du,-inf,inf

Now fixing abs value

1/((2π)*(i*k))*∫e

^{λ/(i*k)*u}e

^{(-u)},du,-inf,o

the integrand for one half of the number line looks like:

E

^{(u*(λ/(ik)-1)}

For which i get: after limits are taken for that half of the integral

(1/((λ/ik)-1))

Then similar integral for other half

Is this the right track or am i totally off?