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## Homework Statement

Consider a harmonic oscillator with mass=0.1kg, k=50N/m , h-bar=1.055x10

^{-34}

Let this oscillator have the same energy as a mass on a spring, with the same k and m, released from rest at a displacement of 5.00 cm from equilibrium. What is the quantum number n of the state of the harmonic oscillator?

## The Attempt at a Solution

ok, so i was wondering, why can't i use angular momentum quantization?

meaning mvr = n(h-bar)

so i divide both sides by r

^{2}

i get m(k/m)

^{-1/2}=n(h-bar)/r

^{2}

make n subject, sub in all values, i get 5.29*10

^{31}.. which happens to be twice the correct answer.

so did i make a careless mistake somewhere? or was i never been able to use this formula? thanks!