Quantum Measurement: Explaining Collapse & CPTP

In summary: The role of tensor products in quantum information theory is to allow for the encoding and decoding of information.
  • #1
aaaa202
1,169
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I am taking a course in quantum information theory. In this theory, the state of a system is given by a density matrix, while a measurement is completely positive, trace preserving map of the form:

Λ = ∑il i >< i l ⊗ Λi

, where Λi is completely positive.

Can anyone tell me how this is equivalent to the usual definition of a measurement on a quantum state, where the state is collapsed into some eigenstate of the operator measured.

Also it seems crucial to quantum information theory that quantum channels are completely positive and trace preserving. The trace preserving part I get since you want the state of the system to remain and allowed quantum state. But why is the completely positive part needed?
 
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  • #2
The question Intuition on positive-operator valued measures (POVM) on the physics stackexchange might be useful to you.

The "usual" definition of a measurement that you're thinking about is "Projective measurements". They're defined in terms of an "observable". The observable is a Hermitian matrix, the possible measurement outcomes correspond to the matrix' eigenvalues, and the measurement outcome tells you that the state is now aligned with the eigenvector(s) corresponding to the measured eigenvalue.

In quantum information land we often use a different abstraction for measurement: POVM measurements. They're a different way of specifying the same thing. Their advantage is mostly that they abstract away some boring details. A POVM is a set of positive operators ##E_m## satisfying ##\sum_m E_m = I##. The probability of outcome ##m## given the density matrix ##\rho## of a state is ##tr(E_m \cdot \rho)##, etc.

The reason each ##E_m## is a positive operator comes down to the fact that they must sum to identity and that they are secretly, under the hood, the product of a "measurement operator" and its adjoint: ##E_m = M_m^\dagger M_m##. Consider what happens to an orthogonal eigendecomposition of ##M_m## when you multiply by ##M_m^\dagger##. An eigenvalue ##a e^{i b}## will get multiplied by its conjugate ##a e^{-i b}##, causing the phase factors to cancel and leaving a non-negative ##a## as the new eigenvalue.

The motivating reason for the eigenvalues of the ##E_m##'s to be positive, instead of using some totally different definition and constraints, probability has to do with wanting something that acts like probabilities.

(Note: You only need the ##M_m## values when working with pure states described by a vector instead of a density matrix.)

(Note: do not confuse "measurement operator" with "observable".)
 
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  • #3
aaaa202 said:
Can anyone tell me how this is equivalent to the usual definition of a measurement on a quantum state, where the state is collapsed into some eigenstate of the operator measured.

You really need to see an axiomatic development - see post 137:
https://www.physicsforums.com/threads/the-born-rule-in-many-worlds.763139/page-7

To see how its equivalent to usual QM see the first 3 chapters of Ballentine. I wish I could explain the last bit simply - but it requires a long explanation with some tedious math.

Thanks
Bill
 
  • #4
aaaa202 said:
how this is equivalent to the usual definition of a measurement on a quantum state, where the state is collapsed
It is not equivalent but far more flexible. The latter is a very special case, only realized in measurements of discrete variables and when you obtain perfect information.
aaaa202 said:
it seems crucial to quantum information theory that quantum channels are completely positive and trace preserving.
Complete positivity is essential for adequate behavior under composition of subsystems (tensor product formation), and trace preservation is needed to ensure that after a signal passing an instrument, all probabilities still add up to one. When properly modeled, all physical processes satisfy both conditions automatically.

Relevant Wikipedia articles are
https://en.wikipedia.org/wiki/Quantum_operation
https://en.wikipedia.org/wiki/POVM
 
  • #5
Okay so I think I can conclude that I am trying too hard to make sense using ideas from previous courses in quantum mechanics. But then I need to get used to this new way of thinking.

As stated a measurement is apparently represented by an instrument, which is a CPTP map of the form:

Λ(X) = Σ li><il ⊗ Λi

So can anyone tell me exactly what this operator does to the state of a system. As discussed the state of a system is represented by some density matrix ρ, so how should I act with Λ on this?
My book says without proof that the probability to obtain outcome i is TrΛi and that the post-measurement state is 1/p(i) * Λi. Can anyone clarify why this is? (I think you have already touched upon it, but I am not sure I understand it).
Also can someone say in a few words what the role of tensor products in quantum information theory is? From my understanding they are used when you divide a larger system into subsystems, but I am not sure about this. For example when a quantum channel is applied to part of larger system its action is Λ⊗id
 
  • #6
I guess what I want to know is also what is the interpretation of a measurement when we write it as Λ(X) = Σ li><il ⊗ Λi? What does the tensor product do?
 
  • #7
Could you include some more context around the equation? It looks like some kind of "measure these qubits then, if the outcome was 0, do measurement A, else if the outcome was 1, do measurement B, else if ..." observable instead of a general definition.
 
  • #8
Well my book just says that on the attached picture. In general a measurement is represented as an instrument which is a map of the type above. When this acts on the system the probability to obtain outcome i is TrΛi and that the post-measurement state is 1/p(i) * Λi. But I don't know how to see this.
 

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  • #9
It looks like a definition for a specific kind of measurement, defined in terms of a POVM. So you should learn about POVMs in order to understand this definition. I think the general idea is that the ##\left| i \right\rangle##s are the instrument outputs and the ##\Lambda_i##s are the corresponding states of the system given the output. Other than that it looks unfamiliar to me.
 
  • #10
aaaa202 said:
Λ(X) = Σ li><il ⊗ Λi

So can anyone tell me exactly what this operator does to the state of a system?
Look at the attached picture you gave in the link. a measurement maps a density matrix (it is your X) to two things: the output li><il and Λi(X)
 
  • #11
For every state ##\rho## to be measured the initial pointer state of the apparatis is its ground state |0><0|.
We start from ##|0><0| \otimes \rho##
then during the premeasurement they interact to become
##\Sigma |i><i| \otimes \Lambda_i(\rho)##
We could write in an abstract way that we have a map from ##H_a \otimes H_b## to itself but as the ground state of the apparatus is a constant we say that the channel sends ##H_a## to ##H_a \otimes H_b##
 

1. What is quantum measurement?

Quantum measurement is the process of observing a quantum system and obtaining information about its state. This involves interactions between the system and a measurement apparatus, resulting in a collapse of the quantum state into one of the possible measurement outcomes.

2. What is the collapse of the wave function?

The collapse of the wave function is a key aspect of quantum measurement. It refers to the sudden change in the quantum state of a system as a result of measurement, from a superposition of possible states to a single definite state. This is often represented by the mathematical concept of wave function collapse.

3. How does quantum measurement relate to the CPTP theorem?

The CPTP (completely positive, trace-preserving) theorem is a fundamental principle in quantum mechanics that describes the evolution of quantum systems. In the context of quantum measurement, the CPTP theorem explains how the measurement process can be described as a trace-preserving operation that preserves the positivity of the system's density matrix.

4. What is the role of entanglement in quantum measurement?

Entanglement is a phenomenon in quantum mechanics where two or more particles become intrinsically linked, so that measuring the state of one particle affects the state of the other(s). In quantum measurement, entanglement can play a crucial role in determining the outcomes of measurements and understanding the collapse of the wave function.

5. How does quantum measurement impact our understanding of reality?

The concept of quantum measurement challenges our traditional understanding of reality, as it suggests that the act of observation can fundamentally alter the state of a system. It also raises questions about the role of consciousness in the measurement process and the nature of reality at the quantum level. Ongoing research and debate in this area continue to shape our understanding of the universe.

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