Quantum mechanics

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An electron in the hydrogen atom makes a transition from an energy state of principle quantum number N(i) to the N=2 state. If the photon emitted has a wavelength of 434 nm, what is the value of N(i)?

....no idea
 

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cepheid
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DennisG said:
An electron in the hydrogen atom makes a transition from an energy state of principle quantum number N(i) to the N=2 state. If the photon emitted has a wavelength of 434 nm, what is the value of N(i)?

....no idea
Hmm...my guess is that you determine the photon energy using the relation

[tex] E = \frac{hc}{\lambda} [/tex]

Then you look up how large an energy transition (in "steps" of N) down to N = 2 is required for a photon of that energy to be emitted.

If I've made a mistake, someone please tell me.
 
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Tide
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DennisG said:
An electron in the hydrogen atom makes a transition from an energy state of principle quantum number N(i) to the N=2 state. If the photon emitted has a wavelength of 434 nm, what is the value of N(i)?

....no idea
Does the term "Balmer Series" ring a bell?
 

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