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Quantum mechanics

  1. Sep 20, 2004 #1
    An electron in the hydrogen atom makes a transition from an energy state of principle quantum number N(i) to the N=2 state. If the photon emitted has a wavelength of 434 nm, what is the value of N(i)?

    ....no idea
     
  2. jcsd
  3. Sep 21, 2004 #2

    cepheid

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    Hmm...my guess is that you determine the photon energy using the relation

    [tex] E = \frac{hc}{\lambda} [/tex]

    Then you look up how large an energy transition (in "steps" of N) down to N = 2 is required for a photon of that energy to be emitted.

    If I've made a mistake, someone please tell me.
     
  4. Sep 21, 2004 #3

    Tide

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    Does the term "Balmer Series" ring a bell?
     
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