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Quantum number

  1. Mar 6, 2006 #1
    a mass of 10^-6 grams is moving at a speed of 0.1 cm/s in a box 1 cm in length. Treating this as a 1-D infinite square well, i am to calculate the quantum number n:

    i was wondering if I am setting this up correct:
    [tex]\frac{1}{2} * 10^{-6 }g * 0.1 cm/s = \frac{n^2 \pi^2 \hbar ^2}{2*10^{-6 }g * 1cm^2}[/tex]
  2. jcsd
  3. Mar 6, 2006 #2

    Meir Achuz

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    Just use v^2 on the LHS.
  4. Mar 7, 2006 #3
    so [tex]E= \frac{n^2 \pi^2 \hbar ^2}{2mL}[/tex]
    is really kinetic energy?
  5. Mar 7, 2006 #4
    Not exactly. E = T + V. But since this is an infinite square well and the region you have has V defined as zero...

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