A certain photoelectric surface has a threshold frequency of 4.62 X 10^14 Hz.
a) What is the photoelectric work function in joules?
b) The surface is illuminated with light that has a frequency of 5.2 X 10^14 Hz. What is the kinetic energy of the electrons ejected from the surface? Answer in joules and electron volts.
1 eV = 1.6 X 10^19 J
W = hf
The Attempt at a Solution
a) 3.06 X 10^-19 J
b) I need help on! I have no idea which equation to use, etc. Thanks!