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Homework Help: Quck Voltage Question (Power)

  1. May 31, 2007 #1
    1. The problem statement, all variables and given/known data
    a 60 W lamp has a potential difference of 120 V across its terminals. at what rate is electrical energy transformed into heat at the lamp?


    2. Relevant equations



    3. The attempt at a solution

    60 W: 60/120 = 0.5A (0.5 A)(120V) = 60 J/sec
     
  2. jcsd
  3. Jun 1, 2007 #2
    That's correct. The definition of power, which is 60 W, is the rate electrical energy is transformed. You don't need to do any calculations. The answer is given.
     
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