1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Question 1st law of Thermodynamics

  1. Nov 20, 2003 #1
    Hi
    I have a question please can you give me a hint how to solve it. It is in thermodynamics

    A vertical piston-cylinder device initially contains 0.01 m^3 of steam at 200 C. The mass of the frictionless piston is such that it maintains a constant pressure of 500 kPa inside. Now steam at 1 MPa and 350 C is allowed to enter the cylinder from a supply line until the volume inside doubles. Neglecting any heat transfer that may have taken place during the process, determine (a)the final temperature of the steam in the cylinder and (b)the amount of mass that has entered.

    This is were my solution but i couldn't complete it:

    State(1):500 kPa, 200 C, 0.01 m^3
    State(2):500 kPa, 0.02 m^3
    at the inlet: Pi=1 MPa, Ti=350 C

    I've found that state 1 and the steam entered are super-heated and i got specific volume for the inlet and state 1 also the h and u from the table of super-heated water vapor

    then got m1=V1/v1

    m(inlet) = m2-m1

    -W + (m h)inlet = m2 u2 - m1 u1....(1)

    m of the inlet, m2 and u2 are unknowns

    W=P(V2 - V1) = 500(0.02 - 0.01) = 5kJ

    or we can write eq(1) as:

    m2 h2 - m1 h1 - (m h)inlet = 0

    m2, h2 and m of the inlet are unknowns

    since h = Pv + u

    please can you help me?
     
  2. jcsd
  3. Nov 20, 2003 #2
    My naive approach is:

    - since the additional gas has double pressure, it has double density. Thus, the final mass is 3 times the initial mass.

    - since temperature is energy per particle, the resulting temperature is (T1 + 2 T2)/2, where everything is in Kelvins.
     
  4. Nov 20, 2003 #3
    thank you

    i knew how to solve
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Question 1st law of Thermodynamics
Loading...