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kyang002
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A metallic wire has a diameter of 4.12 mm. When the current in the wire is 8 A, the drift velocity is 5.4*10^-5 m/s.
What is the density of free electrons in the metal?
I have considered a wire of cross-sectional area A, with current I. V is the drift velocity of the free charges in the conductor and n is the number of charged particles per unit volume. Then the current is given by I = nqva, where q is the magnitude of the charge on a charge carrier.
I = 8
n = density??
A = (2.06)^2 * 3.14
v = 5.4 x 10^-5
q = ??
I am unsure of how to finish the problem. We are looking for n. But what is q? Are all my other numbers correct?
What is the density of free electrons in the metal?
I have considered a wire of cross-sectional area A, with current I. V is the drift velocity of the free charges in the conductor and n is the number of charged particles per unit volume. Then the current is given by I = nqva, where q is the magnitude of the charge on a charge carrier.
I = 8
n = density??
A = (2.06)^2 * 3.14
v = 5.4 x 10^-5
q = ??
I am unsure of how to finish the problem. We are looking for n. But what is q? Are all my other numbers correct?