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Question about a limit

  1. Sep 28, 2011 #1
    x[itex]\stackrel{Lim}{\rightarrow}[/itex]infinity ([itex]\sqrt{x^{2}+1}[/itex])[itex]-1[/itex]

    Couldn't I just inset 0 for x and end up getting [itex]\sqrt{1}[/itex]?

    The book tells me to rewrite this problem by its conjugate.

    My question is why? Thanks
    Last edited: Sep 28, 2011
  2. jcsd
  3. Sep 28, 2011 #2


    Staff: Mentor

    As you have written it,
    [tex]\lim_{x \to \infty}\sqrt{x^2 + 1} - 1 = \infty[/tex]
    You seem to be a little confused in this problem. Why would you put in zero for x when the limit is as x goes to infinity?
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