- #1
tony24810
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As shown in the picture, area of shaded region is required.
By setting formula on xy plane, the point of intersection can be deduced and hence calculated by 2 triangles and 1 square.
from my calculation, set left bottom corner as (0,0), then point of intersection is (7/21/47,1/23/47), and area of shaded region would be 4/37/47 cm^2 (4.7872 cm^2).
However, the question requires that no methods beyond year 9 are to be used.
I have tried mainly simultaneous equations mainly, adding subtracting etc and couldn't figure this out.
someone please help.well I'm not sure if this should be posted on homework section or other section, please do let me know if I'm making a mistake, thanks
By setting formula on xy plane, the point of intersection can be deduced and hence calculated by 2 triangles and 1 square.
from my calculation, set left bottom corner as (0,0), then point of intersection is (7/21/47,1/23/47), and area of shaded region would be 4/37/47 cm^2 (4.7872 cm^2).
However, the question requires that no methods beyond year 9 are to be used.
I have tried mainly simultaneous equations mainly, adding subtracting etc and couldn't figure this out.
someone please help.well I'm not sure if this should be posted on homework section or other section, please do let me know if I'm making a mistake, thanks
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