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Introductory Physics Homework Help
Question about charged capacitors and inserting a dielectric into one
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[QUOTE="Kaushik, post: 6371842, member: 664203"] [B]Homework Statement:[/B] The parallel combination of two air filled parallel plate capacitors of capacitance ##C## and ##nC## is connected to a battery of voltage, ##V##. When the capacitors are fully charged, the battery is removed and after that a dielectric material of dielectric constant ##K## is placed between the two plates of the first capacitor. The new potential difference of the combined system is? [B]Relevant Equations:[/B] ##Q = CV## ##C_{eq}= C_1 + C_2## for parallel ## \frac{1}{C_{eq}}= \frac{1}{C_1} + \frac{1}{C_2}## for series First when it is connected to the battery, the capacitors start accumulating charges such that the potential difference equals that of the battery. Then the current stops flowing. ##Q_1 = CV## ##Q_2 = nCV## Where 1 and 2 represent the capacitor with capacitance C and nC respectively Then, when we remove the battery and add a dielectric between the capacitor of capacitance ##C## (##C_{new} = KC##), the potential difference across it reduces. Now, the capacitor 2 starts behaving like a battery, providing charge to the capacitor 1. After this, how can I proceed? [/QUOTE]
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Introductory Physics Homework Help
Question about charged capacitors and inserting a dielectric into one
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