Hi. It's me again with another confusing circuit problem. The first attached image below shows ib going from right to left through the 11Ω resistor and ib is given -2A. In the solutions manual of the book, it has reversed the direction of the current as in going from left to right and taken the value 2A. My questions is, why has the solutions manual reversed the direction and not just solved it from left to right and taking the current -2A? Could it be solved it both ways?