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Question about displacement

  1. Feb 19, 2012 #1
    We can have the velocity as v1 or v2 , time also, but In some cases i see it in displacement for e.x
    ##x=x_0+v_0 t + \frac{1}{2} at^2##, how can it be displacement 1 , displacement 2, can some one explain? Is it the displacement of the body 1, and displacement of the body 2 or what?
     
  2. jcsd
  3. Feb 19, 2012 #2

    Doc Al

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    Staff: Mentor

    In that version of the kinematic equation, x0 is the initial position (at time t = 0), v0 the initial velocity, and x is the position at time t.
     
  4. Feb 19, 2012 #3
    Wouldn't that be the length of the body, like if the length of the body is 5m and distance 10m, the displacement would be 5m?
     
  5. Feb 19, 2012 #4

    Doc Al

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    Staff: Mentor

    No. Kinematics describes the movement of a body, not its dimensions.
     
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