So... I took this equation and integrated it:(adsbygoogle = window.adsbygoogle || []).push({});

e^(x^2)=1+x^2+(x^4)/2!...

∫e^(x^2)dx=(x+x^3/3+(x^5)/(5.2!)+...)+c

And then I started assigning values to x to get some weird sums. And turned them into sequences. Like for x=2

I got this sum:

2+8/3+16/5+...=S

And turned it into this:

2,8/3,16/5,...

Then I tried calculating the smallest x value for this equation, and that's where I ran into problems because you get the samething as before but this time you have to equal it to 0:

1+x^2+(x^4)/2!...=0

e^(x^2)=0

Does that mean that the smallest x value for this equation is undefined? If it isn't then what is it?

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# Question about e^(x^2)

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