So... I took this equation and integrated it: e^(x^2)=1+x^2+(x^4)/2!... ∫e^(x^2)dx=(x+x^3/3+(x^5)/(5.2!)+...)+c And then I started assigning values to x to get some weird sums. And turned them into sequences. Like for x=2 I got this sum: 2+8/3+16/5+...=S And turned it into this: 2,8/3,16/5,... Then I tried calculating the smallest x value for this equation, and that's where I ran into problems because you get the samething as before but this time you have to equal it to 0: 1+x^2+(x^4)/2!...=0 e^(x^2)=0 Does that mean that the smallest x value for this equation is undefined? If it isn't then what is it?