- #1

predentalgirl1

- 67

- 1

**An ac generator with a maximum emf of 400 V is to be constructed from wire loops (radius 0.15 m). It will operate at a frequency of 60 Hz and use a magnetic field of 200 mT. How many loops will be needed?**

**Given that,**

Maximum emf = 400 V

Radius = 0.15 m

Frequency (υ) = 60 Hz

Magnetic field = 200 mT

We have,

Maximum emf = Bnaω where ω = 2π υ

V = 200 x 10 ^-6 x n x π x (0.15)^2 x 2 π x 60

Therefore n = 400 x 7 x 100 x 100 x 7/200 x 10-6x 22 x 15 x 15 x 2 x 22 x 60

= 7.5 x 10^4

Maximum emf = 400 V

Radius = 0.15 m

Frequency (υ) = 60 Hz

Magnetic field = 200 mT

We have,

Maximum emf = Bnaω where ω = 2π υ

V = 200 x 10 ^-6 x n x π x (0.15)^2 x 2 π x 60

Therefore n = 400 x 7 x 100 x 100 x 7/200 x 10-6x 22 x 15 x 15 x 2 x 22 x 60

= 7.5 x 10^4