1. Sep 30, 2005

jakeowens

If your on a planet that has 4x as much mass as earth, but only 2x the diameter, would you weigh 4x as much as you do on earth? Does the diameter of the planet even matter? or is it only the mass that affects how much you weigh.

Thanks

2. Sep 30, 2005

misogynisticfeminist

hmm, i'll try,

weight is w=mg, where g is the gravitational field strength at a point. Weight is the G force acting on you.

using $$F= G \frac{Mm}{r^2}$$ where M is mass of earth and r is radius of earth, according to your example,

$$F= G \frac{4Mm}{(\frac{1}{2r})^2}$$

notice that half r is being squared, this gives you a quarter r ! If you bring everything up, and simplify,

you get,

$$F= 16 G \frac{Mm}{r^2}$$

so it weighs 16 times more on earth.

The diameter of the planet matters, because the equation depends on r.

Last edited: Sep 30, 2005
3. Sep 30, 2005

Grogs

I think this equation should be:

$$F= G \frac{4Mm}{(2r)^2}$$

The 4 and the 22 will cancel out and you'll end up with 1g.

4. Oct 1, 2005

Robokapp

just sitck some values into it and see how it varies. pick F=forget about constant F=Mm/d^2 and replace everytihng you don't need by 1 and everytihng you need by 2 and 4 accordingly. work smart...work simple.

F=4Mm/(2D)^2 so the 4 cancels the 2^2.

5. Oct 1, 2005

misogynisticfeminist

ohhh thought the radius was half.