1. Dec 23, 2011

### Miike012

I posted the paragraph with the inequality where I am confused...

I also added a portion i highlighted in red

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2. Dec 26, 2011

### Curious3141

The text in the image is not very clear. One of the 'I's appears to have a line on the bottom, the other has the line on top.

Regardless, the portion in the red box looks nonsensical. Everything before that makes sense.

Let the s integral be represented by S, and the t integral be represented by T. Let's call the first I with the bar on the bottom A and the second I with the bar on top B.

So the inequalities are:

$S \leq A \leq T$ ---(1)

and $S \leq B \leq T$ ---(2)

Take (-1) times inequality 1. Remember to reverse all the signs:

$-S \geq -A \geq -T$

Reverse the order of the terms (just write it backward):

$-T \leq -A \leq -S$ ---(3)

$S-T \leq B-A \leq T-S$