- #1

- 79

- 0

## Main Question or Discussion Point

I was wondering if I did this correctly:

Sketch the region enclosed by y = x and y^2=x+2 and then determine its area.

I got the area enclosed to be x = 0, x = 2.

Then I used Integral from 0 to 2 (x+2)^(1/2) - (x) = [(2/3)(x+2)^(3/2) - (x^2/2)] evaluated at 2 and 0 which = 10/3

Sketch the region enclosed by y = x and y^2=x+2 and then determine its area.

I got the area enclosed to be x = 0, x = 2.

Then I used Integral from 0 to 2 (x+2)^(1/2) - (x) = [(2/3)(x+2)^(3/2) - (x^2/2)] evaluated at 2 and 0 which = 10/3