Consider two light rays propagating from point A to point B in the figure, which are 3(lambda)/4 apart. One ray follows a straight path, and the other travels at a 60 degree angle to that path and then reflects off a plane surface to point B. Both rays have wavelength lambda. View Figure
Find the phase difference between these two rays at point B. Answer in terms of pi.
No equations were provided. But according to my handy textbook:
Phase Difference = 2(pi)(change in x)/(lambda) + change in initial phase
The Attempt at a Solution
(Phase Difference) = 2(pi)[3lambda/4lambda] + (60 degrees * 2pi/360 degrees)