Insights Blog
-- Browse All Articles --
Physics Articles
Physics Tutorials
Physics Guides
Physics FAQ
Math Articles
Math Tutorials
Math Guides
Math FAQ
Education Articles
Education Guides
Bio/Chem Articles
Technology Guides
Computer Science Tutorials
Forums
General Math
Calculus
Differential Equations
Topology and Analysis
Linear and Abstract Algebra
Differential Geometry
Set Theory, Logic, Probability, Statistics
MATLAB, Maple, Mathematica, LaTeX
Trending
Featured Threads
Log in
Register
What's new
Search
Search
Search titles only
By:
General Math
Calculus
Differential Equations
Topology and Analysis
Linear and Abstract Algebra
Differential Geometry
Set Theory, Logic, Probability, Statistics
MATLAB, Maple, Mathematica, LaTeX
Menu
Log in
Register
Navigation
More options
Contact us
Close Menu
JavaScript is disabled. For a better experience, please enable JavaScript in your browser before proceeding.
You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an
alternative browser
.
Forums
Mathematics
General Math
Question about Inverse Derivative Hyperbola function
Reply to thread
Message
[QUOTE="Vividly, post: 6553828, member: 662264"] [B]TL;DR Summary:[/B] Question about inverse Tanhx Im confused about a certain part of solving an equation. So I used the hyerbola formula to find the answer but I think I did the math wrong. X^2-y^2=c^2 X=1 Y= (2x^5-1)^2 I did the calculations as you can see in the picture but I know I messed up on the square root part. When you square one side you have to square the whole other side. So Far I got 1^2-((2x^5-1)^2)^2 =c^2 And as you can see in the picture the math is incorrect due to the process that's suppose to be done in math. When I square both sides I get a different answer when I simplify. As you can see on the paper that where I am stuck because the answer is 5/2x-2x^6 [/QUOTE]
Insert quotes…
Post reply
Forums
Mathematics
General Math
Question about Inverse Derivative Hyperbola function
Back
Top