- #1

- 304

- 14

## Homework Statement

## Homework Equations

## The Attempt at a Solution

How to do part biii?

I tried to find change of U and W, then use ΔU-W=Q=0.

I can find the change in U by using the fact the rms of the x-component of the velocity is doubled. Therefore, originally, if isotropic <c

^{2}> = <v

_{x}

^{2}>+<v

_{y}

^{2}>+<v

_{z}

^{2}> = 3<v

^{2}

_{x}>,

now the new <v

_{x}

^{2}> is 4 times the old one, so the new mean square <c'

^{2}>=6<v

_{x}

^{2}>=2<c

^{2}>, so the new internal energy is double the old one. How about the work done? How to find it? I have only learnt how to find adiabatic, isothermal and constant volume work done.