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Question about light and blackholes

  1. Nov 13, 2003 #1
    i was just wandering..... at the point where gravity is strong enough to be greater than the kinetic energy of which light possesses, do photons of light actually radiate some distance from the collapsed star then slow to rest and fall back to the surface, as a cannonball being shot straight up in Earth's atmosphere would, or at this point are the particles simply not capable of being emitted. or is their some other explanation of which i have not accounted for.
    thx,
    magus
     
  2. jcsd
  3. Nov 13, 2003 #2
    I wouldn't say that "gravity is strong enough to be greater than the kinetic energy [of light]". But I understand the gist of your question. In Newtonian gravity, light emitted from the surface of a "Newtonian black hole" will travel some distance away from the hole, then fall back. But in true relativistic gravity, light emitted at or within the event horizon of a black hole cannot travel outward at all: spacetime curves the path of the light so it always falls inward.
     
  4. Nov 13, 2003 #3
    so it basically depends on which conception of gravity is actually correct?
     
  5. Nov 13, 2003 #4
    Yes. We know that Newton's theory of gravity is incorrect. We have good evidence that Einstein's theory works in many circumstances, but we don't have much in the way of direct tests of that theory near black holes. What indirect tests we do have still bear out Einstein's theory, so most astrophysicists would probably bet at the 95% level or higher that light cannot escape a black hole to any distance.
     
  6. Nov 16, 2003 #5
    X-rays are able to escape (emit from) a black hole, and X-rays are a form of light. Do they travel faster than light to be able to escape the black hole?
     
  7. Nov 16, 2003 #6
    X-rays are not able to escape from a black hole. The X-rays we see indicating the presence of a black hole actually come from matter outside of the black hole.
     
  8. Nov 16, 2003 #7
    Are you talking about the accretion disk?

    Gas and dust surrounding a newborn star, a black hole, or any massive object help it to grow in size by attracting more and more material.

    Does a black hole grow in size relative to the amount of material it attracts?

    I understood that neutron stars bounce X-rays off their mass. Is it possible this can happen with a black hole? X-rays are said to have a very active wave. Could this help them to escape the intense gravity of a black hole? The same high frequency wave of the X-ray probably causes it to bounce off of the white dwarf or neutron star.
     
  9. Nov 16, 2003 #8
    Yes, or particles that are sucked from it and shot up along the magnetic poles.

    A black hole grows in size relative to the amount of mass that falls into it.

    Are you saying that the surface of a neutron star reflects X-rays??

    What? "Active wave"? What is that?

    X-rays can escape the gravity of a black hole if they're emitted outside of it and pointed in the right direction; so can light of any other frequency, equally well. Nothing can escape from inside a black hole.
     
  10. Nov 17, 2003 #9
    Hi,

    I think you've got the right idea in "balancing" the potential energy of the cannonball with it's kinetic energy but remember, a photon's energy is not kinetic but is linearly related to it's color (frequency). E = hf

    Consider the point where an object's gravitational field is strong enough such that it's escape velocity equals c (i.e. just inside the event horizon of a black hole).

    Since photons always travel at the speed of light, they can't slow down and stop as a cannonball. They do lose energy however as they climb out of a gravitational field by experiencing a decrease in their frequency (they redshift).

    A photon emitted within the event horizon wouldn't get out because its frequency would redshift to 0hz as all the photon's energy was consumed in climbing out of the gravitational field.
     
  11. Nov 17, 2003 #10
    This energy-conservation explanation can sometimes be misleading. It implies that a photon emitted inside a black hole can travel outwards, but will be redshifted out of existence before it gets to the horizon. In reality, it can't travel outwards at all.
     
  12. Nov 17, 2003 #11
    You're right. I should have said "... the photon's energy would be consumed as the photon attempted to climb out of the gravitational field."
     
  13. Nov 17, 2003 #12
    thx for the insight, the explanations made sense, and just yesterday my physics instructor mentioned that that was probably what happened.

    i now have a few more questions however. It was mentioned that the photon actually does not move outward at all. How does it redshift without moving at all, and what actually happens to the light when it reaches 0hz.
     
  14. Nov 17, 2003 #13
    There's a difference between "not moving outward" and "not moving". A photon always moves at the speed of light according to any local inertial observer.

    Light never actually reaches 0 hz according to anybody; you'd have to travel away from it at the speed of light for it to be redshifted down to zero.
     
  15. Nov 17, 2003 #14
    i think i have the idea that the photon simply vanishes, thus their is nothing to see.im not sure if thats right but its a guess.:smile:
     
  16. Nov 17, 2003 #15
    Well, actually I think somebody's said this since I remember reading it several times in the past. But I've been wrong before so I did some calculations and came up with this:

    Since GR tells us that the ratio of a photon's gravitationally shifted frequency to the original frequency is:

    [tex]
    \nu_s / \nu_o = \sqrt{1 - \frac{2GM}{c^2r}}
    [/tex]

    Where M is the mass of the gravitating body, r is the distance from it, G is the Grav. constant and c is the speed of light.

    The photon redshifts to 0 Hz when:

    [tex]
    \nu_s / \nu_o = 0
    [/tex]

    Which happens when:

    [tex]
    M/r = \frac {c^2}{2G}
    [/tex]

    or where:

    [tex]
    r = \frac {2GM} {c^2}
    [/tex]

    Which is the Schwarzschild radius (event horizon) of a black hole. So it seems to be a valid assumption that if any photon could be emitted within the event horizon, it would also redshift to 0 Hz. But that's just my opinion.

    I believe there's another way for a photon to be redshifted down to 0 Hz too but that involves cosmological expansion which is not really the topic of this thread.

    Cheers, HB
     
  17. Nov 17, 2003 #16
    Your formula applies to the redshifting of a light ray that is emitted at some r>rS and reaches an observer at infinity. It does not really make sense to apply it to a light ray that is emitted at r=rS, because such a light ray never leaves the horizon at all, let alone reaches an observer at infinity who can measure its wavelength.
     
  18. Nov 17, 2003 #17
    Sorry, I mean energetic wave. X-rays have smaller/shorter wavelengths and so they have higher energy than ultraviolet waves or other light waves. Thank you Ambitwistor.
     
  19. Nov 20, 2003 #18
    Gravitons escape the warp of a black hole with no problem and with no loss to gravitational energy.

    Does that mean gravity travels faster than light (escaping the event horizon of a black hole?)
     
    Last edited: Nov 20, 2003
  20. Nov 20, 2003 #19
    Virtual gravitons escape, but since they are not real, they do not carry any real energy, information, or anything else observable out of the black hole.

    When people speak of "the speed of gravity", they mean the speed at which observable gravitational influences, i.e., changes in the gravitational field, propagate. According to that definition, the speed of gravity is the same as the speed of light.
     
  21. Nov 22, 2003 #20
    Can a gravitational field be viewed simply as the sphere of influence or effect generated by a mass? Are there actual waves of gravity or simply a sphere of gravitationally influenced events that demonstrate the effects of a gravitational source?

    How do we observe and verify something going faster than light?
     
    Last edited: Nov 22, 2003
  22. Nov 22, 2003 #21
    I'm not sure what the difference is. Take, say, electromagnetic radiation (light): "Are there actual waves of electromagnetism, or simply a sphere of electromagnetically influenced events that demonstrate the effects of an electromagnetic source?" The answer to this question is the same as the answer to the corresponding gravitational question, but I don't know whether that answer is "yes" or "no" because I don't understand the question.

    Well, here is one way: send a wave past two detectors. See how long it takes between reaching one and reaching the other. Knowing the distance between them, determine its speed.
     
  23. Nov 23, 2003 #22
    When a wave of water moves a leaf of seaweed we can say the mass of water and its motion are the cause of the event. When an object falls to the ground is this caused by a wave of gravity or a condition created by a source of gravity?

    To put it another way, when there is an eclipse and the earth is in shadow, there is no "shadow wave" emanating from the moon, the shadow is simply an effect of the moon blocking the sun, there are no "shadowtons" or shadow waves.

    So what I'm asking is does gravity emanate from a source as a wave, in the way that light radiates from a source, or are we simply seeing the tell tale effects of gravity within a defined sphere of an inert source?
     
  24. Nov 23, 2003 #23
    A static gravitational field (such as, more or less, the Earth's gravitational field) doesn't have any gravitational waves, but objects still fall. (Likewise, the electric field around a point charge doesn't have any electromagnetic waves, but charges are still attracted or repelled from it.) Gravitational waves are changes in the gravitational field, just like electromagnetic waves (light) are changes in the electromagnetic field.

    I think you are confusing some issues.

    Gravitational waves can emanate from a source as a wave, analogous to how light (electromagnetic waves) radiates from a source. But electromagnetic waves are not responsible for, say, the electrostatic attraction (or repulsion) between two charges, nor are gravitational waves intrinsically responsible for the attraction of two masses. Nothing has to "emanate" from a mass or charge, in the sense of some effect propagating at some speed through space, in order for one body to influence another. (But if you change the source, then the effects of that change will propagate out in terms of changes in the field at successively more distant points.)

    I still don't know what you're talking about.
     
  25. Nov 23, 2003 #24
    You've managed to answer my question anyways, thanks.
     
  26. Dec 6, 2003 #25
    This is so heavy spicoli! Nothing escapes the black hole period. NOTHING NOTHING. Not even your thought waves:)
     
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