1. log((x-3)/(x+3)) <= 1

2. 6*9^(1/x) - 13*6^(1/x) + 6*4^(1/x) = 0

So for the first one i didnt get too far. I divided the logarithm and i got:

log(x-3) + log(x+3) <= 1

For the second one i used logarithms and received:

log6 + 1/x*log9 - log13 - 1/x*log6 + log6 + 1/x*log4 = 0

Next:

1/x(log9-log6+log4) + log6 - log13 + log6 = 0

Then:

1/x*(log6) + log(36/13) = 0

and i dont know what to do from here. any help would be apreciated. thanks :)