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Question about Lorentz Transforms

  1. Mar 2, 2013 #1
    If I construct a LT from an un-prime frame to a prime fame: S':=LT(S,v') and another to a double prime system: S":=LT(S,v"), then invert the first: S:=LT(S',-v') and substitute it into the second: S":=LT([LT(S',-v')],v"), I do NOT get the same transform as going directly between the double and single prime frames: LT([LT(S',-v')],v") ≠LT(S',[v"-v']). Does this question make any sense? What am I missing?

    Thanks.
     
  2. jcsd
  3. Mar 2, 2013 #2

    Doc Al

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    Staff: Mentor

    When going from S' to S'', what velocity did you use?

    Realize that if v' is the relative velocity of S and S' and v'' is the relative velocity of S and S'', then the relative velocity of S' and S'' is not simply v'' - v'.
     
    Last edited: Mar 2, 2013
  4. Mar 2, 2013 #3
    Oh? I thought it would be v"-v'. What is it then?

    Thanks.
     
  5. Mar 2, 2013 #4
    Ok, I get it. I have to use the SRT addition of velocities. Thanks!!
     
  6. Mar 2, 2013 #5

    Doc Al

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    Staff: Mentor

    Right!
     
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