I have been working with the following question for quite awhile:(adsbygoogle = window.adsbygoogle || []).push({});

Show that a permutation with an odd order must be an even

permutation.

I have made some progress, but I am having trouble putting it altogether

to make my proof coherent.

This is what i have so far:

Let e= epsilon

Say= ae. ThenBA^(2ka+1)BA^(2ka)=BA^(-1).

Butis even.BA^(2k)=(BA^ka)^2

I know that I am on the right track but I can't seem to put

it altogether. Can someone help me please. If I could

just have it explained Iam sure I will understand.

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# Question about permutations

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